Hi, I can generate a specific image using the following from the Django book.
------------------------------------------------------------------------------------------ from django.http import HttpResponse def my_image(request): image_data = open("/path/to/my/image.png", "rb").read() return HttpResponse(image_data, mimetype="image/png") ------------------------------------------------------------------------------------------ However, I would like the 'image.png' part to be dynamic. I would like the function to render an image from a field lets say called image from a model. Thanks in advance for your help. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---