Wiadomość napisana w dniu 2009-07-29, o godz. 10:04, przez alecs:
> filename = smart_unicode(file.name, encoding='cp1251',
> strings_only=False, errors='strict')
>
> destination = open('%s/%s' % (dir_path, filename), 'wb+')
>
> UnicodeEncodeError ('ascii', u'1.3.1.\u0421\u043b.\u041f
> \u0435\u0440\u0435\u043d\u043e\u0441 \u043e\u0442\u043f
> \u0443\u0441\u043a\u0430.doc', 6, 8, 'ordinal not in range(128)')
>
> What to do ? Thanks!
Your file.name is unicode ubject, so no need to call smart_unicode (it
will first try to encode unicode to bytestring with default codec then
decode with yours). Then, if dir_path is unicode object, the pattern
to build path should be also unicode. I cann't recall if open()
accepts unicode objects as file names, but to be on safe side encode
it to bytestring using codec of your filesystem encoding prior to
passing to open(). Generally do not mix bytestrings and unicode
objects in string interpolation because Python will try to encode/
decode using default codec (which is ASCII, usually) and this is not
the thing you want.
--
Artificial intelligence stands no chance against natural stupidity
Jarek Zgoda, R&D, Redefine
jarek.zg...@redefine.pl
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