On Wed, Jul 29, 2009 at 10:04 AM, Mark<marcwar...@gmail.com> wrote:
>
> Ye thats what I was afraid of - i was hoping there was something in
> the Pagination object that would help me out.
> But I cant see anything.
>
> Maybe someone will point it out after I have implemented the above.
>
> Thanks.
>
> On Jul 29, 3:58 pm, cootetom <coote...@gmail.com> wrote:
>> You may have to do a bit of computation back on the server in python
>> code to get the data you're after. From thepaginationobject you know
>> what page you are currently on, you also know how many items are on a
>> page so:
>>
>> last_item = page_num * items_per_page
>> first_item = last_item - items_per_page + 1
>>
>> Then in your template you can say:
>>
>> Displayingresults{{ first_item }} - {{ last_item }} of {{ p.count }}
>> found.
>>
>> On Jul 29, 3:51 pm, Mark <marcwar...@gmail.com> wrote:
>>
>> > Thanks, but I have been. Its still not clear - To date I have always
>> > beendisplaying
>>
>> > "Page 1 of 23. Showing 10resultsper page"
>>
>> > I am just lost on how to do this.
>>
>> > On Jul 29, 3:44 pm, krylatij <kryla...@gmail.com> wrote:
>>
>> > > Read 
>> > > documentationhttp://www.djangoproject.com/documentation/models/pagination/
> >
>

{{ page.paginator.count }} should be exactly what you want.

Alex

-- 
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right to say it." -- Voltaire
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"Code can always be simpler than you think, but never as simple as you
want" -- Me

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