I've been setting up feeds using the syndication feed framework.
I have a line like this in my urls.py:
(r'^feeds/(?P<url>.*)/$', 'django.contrib.syndication.views.feed',
{'feed_dict': feeds}),
How do I avoid hard-coding the feed urls into my template?
I want to {% url django.contrib.syndication.views.feed.feed_name
params %} in my html templates to generate the <link rel="alternate"/>
tags
...but it doesn't work for me (should it?)
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