This worked fine before but now I get the error
C:\...\Django\sw2\wkw2>csv2json.py csvtest1.csv wkw2.Lawyer
Converting C:\...\Django\sw2\wkw2csvtest1.csv from CSV to JSON as C:...
\Django\sw2\wkw2csvtest1.csv.json
Traceback (most recent call last):
File "C:\...\Django\sw2\wkw2\csv2json.py", line 37, in <module>
f = open(in_file, 'r' )
IOError: [Errno 2] No such file or directory: 'C:\\...\\Django\\sw2\
\wkw2cvtest1.csv'
>From the snippet http://www.djangosnippets.org/snippets/1680/:
31 in_file = dirname(__file__) + input_file_name
32 out_file = dirname(__file__) + input_file_name + ".json"
34 print "Converting %s from CSV to JSON as %s" % (in_file, out_file)
36 f = open(in_file, 'r' )
37 fo = open(out_file, 'w')
It seems to combine the directory name and file name?
Thanks.
On Nov 14, 7:42 am, Zeynel <azeyn...@gmail.com> wrote:
> Great, thank you. When I ran it in the command prompt it worked fine.
> I noticed that the first column needs to be "pk" with rows starting
> with integers.
>
> On Nov 13, 11:24 pm, Karen Tracey <kmtra...@gmail.com> wrote:
>
>
>
> > On Fri, Nov 13, 2009 at 10:57 PM, Zeynel <azeyn...@gmail.com> wrote:
> > > Thanks, I tried but this did not work either:
>
> > > >>> csv2json.py sw.csvwkw1.Lawyer
>
> > > File "<stdin>", line 1
> > > csv2json.py sw.csvwkw1.Lawyer
> > > ^
> > > SyntaxError: invalid syntax
>
> > You need to run the .py script from an OS shell (command prompt), not from
> > within a Python shell.
>
> > Karen
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