Solved: I found this (well hidden) page: http://code.djangoproject.com/wiki/RowLevelPermissions I do not know it is not embedded in Admin.site documentation... and why those fully functional methods are simply hidden in the source code...
On Tue, Jan 19, 2010 at 10:00, Massimiliano della Rovere < massimiliano.dellarov...@gmail.com> wrote: > In simpler terms: > is there a way to filter instances shown with "admin" pages considering the > logged user id? > is there a way to "interface" request.User with admin.ModelAdmin ? > > > On Mon, Jan 18, 2010 at 22:33, Massimiliano della Rovere < > massimiliano.dellarov...@gmail.com> wrote: > >> Greetings, >> I'm here to seek your help: >> I'm new to Django (I have experience with Prado and Zope3 though). >> >> Here is my problem: >> I created a model having - among the other ones - a status field >> (approved, draft, proposed, etc) and a reference to the user that created >> the instance. >> I'd like to use Admin pages (derived from django.contrib.admin and >> django.contrib.auth.models.User) to interact with instances of this models. >> I'm trying to show - in the index (a.k.a. list) page for the instances of >> this models - only the instances created by the logged user, all of them if >> the logged user is the administrator and only the approved ones for >> anonymous users. >> >> I could easily resolve the problem with a simple template & view pair, but >> I was wondering if somehow I can specify in the class derived >> from admin.ModelAdmin and associated to my model somehow that I want to use >> a filter (Manager?) that reads a value from request.User. >> > >--
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