Edward Bartolo:
> KatolaZ wrote:
> >> c) type **ss; // declare a pointer to pointer. System only allocates
> >> space for one address
>
> > C pointers are *always* one variable, precisely a variable large
> > enough to store a memory address on the current architecture.
>
> I think, I did not understand what you want to say. As far as I can
> imagine a pointer to pointer is something like this:
> [pointer1]------>[pointer2]------->[data] int the case of data** dt.
...
To be picky, "int ** id;", just defines an allocates one variable id
that when used like **id will have the type int. It says nothing about
what value id, *id, **id will have, nor if *id or **id will be in any
way useful.
For **id be useful *id has to have some defined value, e.g.
int main(void) {
int data = 4;
int * pointer1 = & data;
int ** pointer2 = & pointer1;
int *** pointer3 = & pointer2;
int **** pointer4 = & pointer3;
/* etc... */
return **** pointer4;
}
$ gcc -Wall a.c; ./a.out; echo $?
4
Regards,
/Karl Hammar
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