The only method that gets automatically executed when you create an instance
of a class is the class constructor. "int index" gets its value when you
utilize that property as you've done in your loop "pwr[i]".
...Glenn
On Mon, Nov 17, 2008 at 6:54 AM, VIKAS GARG <[EMAIL PROTECTED]>wrote:
> using System;
>
> class PwrOfTwo
> {
>
> /* Access a logical array that contains
> the powers of 2 from 0 to 15. */
> public int this[int index]
> {
> // Compute and return power of 2.
> get
> {
> if ((index >= 0) && (index < 16)) return pwr(index);
> else return -1;
> }
>
> // there is no set accessor
> }
>
> int pwr(int p)
> {
> int result = 1;
> for (int i = 0; i < p; i++)
> result *= 2;
>
> return result;
> }
> }
>
> class UsePwrOfTwo
> {
> public static void Main()
> {
> PwrOfTwo pwr = new PwrOfTwo();
>
> Console.Write("First 8 powers of 2: ");
> for (int i = 0; i < 8; i++)
> Console.Write(pwr[i] + " ");
> Console.WriteLine();
>
> Console.Write("Here are some errors: ");
> Console.Write(pwr[-1] + " " + pwr[17]);
>
> Console.WriteLine();
> Console.ReadKey();
> }
> }
>
>
> Once theraot that is the person who also has great knowledge of .NET and
> replies many threads on this community, has told me that whenever we make
> instance of any class that start running immediately. here we are making
> instance of PwrOfTwo Is this making
> public int this[int index] run immediately, this is in line no. 8
> If yes then at that time does the execution of main method stops until the
> control is passed again back to it.
> If it stops running then where is "int index" getting its value from.
> and if I am wrong which line of code is passing its control to indexer that
> is public int this[int index]
>
>
>
>
