`external_ai_queue_in_use()` is supposed to return 1 if the external
channel sequencer is in use by an AI command, else return 0. If the
"read" subdevice (which is the AI subdevice) is not busy then no AI
command is running so the external channel sequencer is not in use, so
the function should return 0. Unfortunately, the function's "read"
subdevice busy test is inverted, so the function always returns 0 when
the "read" subdevice is busy. Worse, if the "read" subdevice is
not busy the subsequent call to `use_internal_queue_6xxx()` results in a
null pointer dereference if a previous AI command used a channel list
with a length greater than 1.
Signed-off-by: Ian Abbott <abbo...@mev.co.uk>
---
drivers/staging/comedi/drivers/cb_pcidas64.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/drivers/staging/comedi/drivers/cb_pcidas64.c
b/drivers/staging/comedi/drivers/cb_pcidas64.c
index aa481c00e8e7..942ba5cd8270 100644
--- a/drivers/staging/comedi/drivers/cb_pcidas64.c
+++ b/drivers/staging/comedi/drivers/cb_pcidas64.c
@@ -3251,7 +3251,7 @@ static inline int external_ai_queue_in_use(struct
comedi_device *dev)
{
const struct pcidas64_board *board = dev->board_ptr;
- if (dev->read_subdev->busy)
+ if (!dev->read_subdev->busy)
return 0;
if (board->layout == LAYOUT_4020)
return 0;
--
2.16.2
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