Ajit Bansode wrote:
> Hi Michael,
> Thanks for the help.
> Actually there are nested funcNs (don't know N) in the application.
> Pls tell me if there is any other way to do this.
I've been thinking ... maybe, if the funcNs are truely nested (ie all
called from func2 or "below"), you probably wouldn't have to change what I
outlined - it shouldn't make a difference. If func1 calls other functions
(say, func2a, func2b, etc) itself, you'll have to do the same for them as
you did for func2 and modify the final calculation in func1:return accordingly.
(the reason I said it'd be trickier was that I started off with a different
example, where it would have been ...)
Michael
> ----- Original Message ----
> From: michael schuster <[EMAIL PROTECTED]>
> To: Ajit Bansode <[EMAIL PROTECTED]>
> Cc: dtrace-discuss@opensolaris.org
> Sent: Friday, 31 August, 2007 11:06:52 AM
> Subject: Re: [dtrace-discuss] Timespent by a function body
>
> Ajit Bansode wrote:
> > Hi,
> > I want to know the time spent by a function.
> > I am using vtimestamp for that but with my script i'm getting
> something like this :-
> > func1 ->
> > func2 ->
> > func2 <- 56624
> > func1 <- 57899
> >
> > I want to know the time spent only by func1().
> > What can I do for that?
>
> something like
>
> func1:entry
> {
> self->s1 = timestamp;
> }
>
> func2:entry
> {
> self->s2 = timestamp;
> }
>
> func2:return
> {
> self->d2 = timestamp - self->s2;
> }
>
> func1:return
> {
> self->d = (timestamp - self->s1) - self->d2;
> }
>
> you'll have to put in proper predicates and zero out the temporary
> variables, but I guess you get the idea. For nested funcN, N > 2, this
> gets a bit trickier, but we'll leave that as an exercise to the reader ;-)
>
> (I haven't tested this, btw ... makes things much more fun, right?)
>
> HTH
> Michael
>
> --
> Michael Schuster Sun Microsystems, Inc.
> recursion, n: see 'recursion'
>
>
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--
Michael Schuster
Recursion, n.: see 'Recursion'
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