On Thu, Dec 18, 2008 at 10:28:22AM +0800, Jason Zhao wrote: > It seems like the 64-bit address not only depends on > shell type, but also depends on utilities(commands) > you run.
The address size depends on the binary type of the program being run by the process you're looking at. Most utilities in /usr/bin are 32-bit programs only, with some having /usr/bin/amd64 and /usr/bin/sparv9 variants. Those utilities are there for a reason. ls(1) has a 64-bit variant because time_t is larger in 64-bit and ls(1) deals with dates. And so on. > I run "/usr/bin/ls" got 32-bit, but "/usr/bin/amd64/ls" > got 64-bit address. Is that because 32-bit application > map to memory with 32-bit address? How the address > space is mapped out for a 64 bit application and for > 32-bit application? ls(1) is also special in that by default you get the 32-bit version -- you have to explicitly run the 64-bit version if you want that version. Nico -- _______________________________________________ dtrace-discuss mailing list dtrace-discuss@opensolaris.org
