You are correct. I had it backwards. ::sigh::
73, Dick
At 6:46 PM -0400 on 6/23/01, you wrote:
> 468/f = length in feet of 1/2 wavelength in feet, but that does not take
> into count that the velocity of propagation is slowed down as travels down
> the
> antenna compared to free space.
>
> (468/f) X .98 is more accurate
>
> 73, Larry K4WLS BSEE PE (Ret)
>
> +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
>
>
>
> ----- Original Message -----
> From: "Dick Flanagan" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Cc: <[EMAIL PROTECTED]>
> Sent: Saturday, June 23, 2001 6:03 PM
> Subject: Re: [DXR] Antenna Question
>
>
> At 11:39 AM -0700 6/23/01, [EMAIL PROTECTED] wrote:
>
>> Anyone know off the top of their head the numerator in the formula for
>> calculating the length of a dipole?
>> I want to say 468?
>
> 468 divided by the frequency in megahertz (468/f) will give you the
> length in feet of a QUARTER-wave. For a dipole you will need to double
> that figure or use 234/f for your original formula.
>
> For example, the length of a dipole for 14.2 MHz would be approximately
> 234/14.2 or 16.5 feet. Start a bit longer than that and trim it to
> length with an SWR bridge.
>
> 73, Dick
> --
> Dick Flanagan W6OLD CFII Minden, Nevada DM09db (South of Reno)
> Visit http://www.cvrc.net/
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--
Dick Flanagan W6OLD CFII Minden, Nevada DM09db (South of Reno)
Visit http://www.cvrc.net/
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