[EMAIL PROTECTED] wrote: >> Over lengthy but interesting article >> >> http://www.zealllc.com/2002/digigold.htm >> >> Kind regards, >> >> [EMAIL PROTECTED] > > incredible -- is that calculation right? > > A 50 lb lump of gold fits in a four inch cube? > > Can someone do the calculation??!
------------------------------------------------------ 1 lb = 16 oz. = 453.6 g ; therefore 50lb = ~22680 g According the the CRC manual gold has a density of ~19.3g/cm^3 at 20 deg. celcius (a comfortabel room temp) A 4 inch cube is a tiny bit less than 10 cm on a side making a cube of a little less than 1000 cm^3 The weight of the cube in question is 1000 x 19.3 = 19300 g. which is equivalent to approximately 42.5 lb . . . a bit less than 50lb, wouldn't you say. At 20 deg. celcius a 50lb square cube of gold would have a volume of approximately 1175.1 cm^3, which is equivalent to a cube with sides of approximately 10.5 cm (~4.25 in.), which is very close to the 4 in. mentioned above. NOTE: 1 in.^3 = ~ 16.39 cm^3 PECB C = W log2(1 + S /N ) http://www.two-cents-worth.com/?pecb www.GoldCom.cc --- You are currently subscribed to e-gold-list as: archive@jab.org To unsubscribe send a blank email to [EMAIL PROTECTED] Use e-gold's Secure Randomized Keyboard (SRK) when accessing your e-gold account(s) via the web and shopping cart interfaces to help thwart keystroke loggers and common viruses.
