the original post meant that ... there were multiple tasters ... i had just
put 10 as an example
thus, in the binomial context ... i was assuming (rightfully or wrongfully)
that n=10 ... that is, if we SCORE across the 10 ... we could have scores
of 0 to 10 ... in terms of how many got the correct orderings
now, it was the p that i was most interested in ... since ... in the
example ... we have no real idea of how many times the Ss might taste and
retaste ... slices and, if multiple ... in what orders ...
given that for any particular S ... the way the problem was posted ... the
correct order could have been (and only) ... SSD ... SDS ... DSS ...
in this sense, there is a 1 out of 3 chance of hitting it correctly ...
but, is the p value in this binomial really 1/3??? is this really a true
binomial case?
does the fact that SSS and DDD are not allowed and, the fact that tasting
one surely has some impact on what you decide about tasting another (hence,
some dependence in the situation) ... take it out of the binomial?
At 09:15 AM 2/26/01 -0600, Mike Granaas wrote:
>Upon rereading Dennis' original question he proposed 10 S, not 10
>trials/S. So, my speculations about sequential trials for a given S are
>not relevant. That will teach me to try and respond on friday afternoons.
>
>Michael
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