Maximize l'delta delta'l on the condition that l'Sigma l=1. Use a 
Lagrange multiplier
lambda to find delta delta'l = lambda Sigma l, which shows Sigma l proportional
to delta.

At 2:47 AM +0000 11/22/99, Brad wrote:
>Thanks. You're right. The numerator should be (L'delta)^2. However, I'm still
>  confused about the solution. How did you arrive at the solution?
>
>Thanks.
>brad
>
>In article <v04220800b45c9787eb74@[204.212.38.187]>,
>   [EMAIL PROTECTED] (Jan de Leeuw) wrote:
>  > This can't be right. Let L->0 then fn -> infty. Probably you want
>  > sqrt(L'Sigma L) in the denom.  In that case, the solution is simply
>  > proportional to sigma^{-1}delta.
>  >
>  > At 4:42 PM +0000 11/20/99, Brad wrote:
>  > >Hello.
>  > >
>  > >I'm trying to maximize (wrt L) the following function:
>  > >
>  > >fn:= (L'delta)/(L' Sigma L)
>  > >
>  > >where L = p x 1
>  > >          delta = p x 1
>  > >          Sigma = p x p
>  > >
>  > >I'd appreciate any help in the matter.
>  > >
>  > >Brad
>  > >
>  > >
>  > >Sent via Deja.com http://www.deja.com/
>  > >Before you buy.
>  >
>  > ===
>  > Jan de Leeuw; Professor and Chair, UCLA Department of Statistics;
>  > US mail: 8142 Math Sciences Bldg, Box 951554, Los Angeles, CA 90095-1554
>  > phone (310)-825-9550;  fax (310)-206-5658;  email: [EMAIL PROTECTED]
>  >     http://www.stat.ucla.edu/~deleeuw and http://home1.gte.net/datamine/
>  > 
>====================================================================== 
>======
>  >           No matter where you go, there you are. --- Buckaroo Banzai
>  > 
>====================================================================== 
>======
>  >
>
>
>Sent via Deja.com http://www.deja.com/
>Before you buy.

===
Jan de Leeuw; Professor and Chair, UCLA Department of Statistics;
US mail: 8142 Math Sciences Bldg, Box 951554, Los Angeles, CA 90095-1554
phone (310)-825-9550;  fax (310)-206-5658;  email: [EMAIL PROTECTED]
    http://www.stat.ucla.edu/~deleeuw and http://home1.gte.net/datamine/
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          No matter where you go, there you are. --- Buckaroo Banzai
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