let's see ... say you have two overlapping distributions ... on the left, 
the null distribution ... and on the right, the assumed to be true sampling 
distribution ...

now, in setting up the power problem ... you have to set alpha ... say that 
is a two tailed .05 test ... and really the upper critical value is of most 
interest ... so, that value might be like a t of 2.02 ... to the right of 
the middle of the null distribution ...

now, depending on what you are allowing power to be ... then, beta is 1 - 
power ... so, say that power is desired to be .7 ... the beta will be .3 ...

that means on the true sampling distribution ... TO THE LEFT OF THE CENTER 
OF THAT TRUE DISTRIBUTION ... beta will be the area FURTHER TO THE LEFT ... 
or, in this case, the lower 30% of the true (distribution on the right) 
sampling distribution ...

that is ... what is about the 97.5 percentile rank for the critical t value 
at the upper end of the null distribution ... will be at the 30 percentile 
rank value in the (hoped for) assumed to be true sampling distribution ...

would that not simply be the t value ... that produces the 30th percentile 
rank?

let's assume for arguments sake .... n = 40 so, we have df = 39 ... in a 
single sample kind of case ...

the critical value for the null (right side of the null distribution) would 
be in minitab

MTB > invcdf .975;
SUBC> t 39.

Inverse Cumulative Distribution Function

Student's t distribution with 39 DF

P( X <= x )          x
     0.9750        2.0227  <<< critical value for null test

MTB > invcdf .3;
SUBC> t 39.

Inverse Cumulative Distribution Function

Student's t distribution with 39 DF

P( X <= x )          x
     0.3000       -0.5287  <<< critical value (where to the left will be 
beta of about .3)

it helps to try to draw out two overlapping distributions ... fill in what 
you know or want ... and then see about solving the problem you have to solve

MT

'm posting this message on behalf of my friend.
>Any help would be greatly appreciated.



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