6 students, 4 tires:
The probability that they all choose the same tire [doesn't matter which] is
(1/4)^5 = 1/1024.
N students, M tires:
(1/M)^(N-1)
(The answer with ^6 or ^N answers a different question: what is the
probability that they all choose the front left-hand tire?)
Fergus
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