Maybe the 162 is related to number of games in a major league regular
season.

Gerry

On Thu, 13 Mar 2003 14:15:03 -0500, Paige Miller
<[EMAIL PROTECTED]> wrote:

>Fred Ettish wrote:
> > I was given this problem and and having some difficulty understanding
> > part of it.
> >
> > The problem involves a .250 hitter who gets 5 at bats per game and
> > the question is ( I think) "What is the expected streak of games
> > where the batter gets a hit?"
> >
> > So
> >
> > The probability of not getting a hit at bat is .750. The probability
> > of no hits at 4 at bats is .750^5 = .237 The probability of at least
> > one hit per game is 1 - .237 = .763
>
>You are in good shape up to here, if my assumption of typographical
>error is correct (specifically, the above should read "probability
>of no hits at 5 at bats")
>
>At this point, to get the expected consecutive number of games in which
>a batter gets a hit, you would have a geometric distribution with
>probability p=0.763 for each trial. Thus, expected value is 1/p = 
>1/0.763 = well you can figure it out from here
>
> > So the longest streak is k where .763^k=1/162
> >
> > Can anyone explain this last step? Why set it equal to 1/162?
>
>I can't explain it.
>
> > Thanks
>
>Now, all of this also makes the assumption that the probability of
>getting a hit each and every at bat is the same, a dubious assumption, 
>but perhaps a place to start.

.
.
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