gamin wrote: > > The books stated answer is : 0.27 > Mine is : 0.2450 [ reasoning as follows : 1- P(no ticket at L1) - P(no > ticket at L2) - P(no ticket at L3) - P(no ticket at L4) ]
You seem to be arguing that P(no ticket)= P(no ticket at L1 OR no ticket at L2 OR ... etc) and that "ticket/no ticket at L1", "ticket/no ticket at L2" etc are mutually exclusive. Both of these are wrong. You should start from P(no ticket)= P(no ticket at L1 AND no ticket at L2 AND ... etc). and then see if "ticket/no ticket at L1", "ticket/no ticket at L2" etc are independent events. . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
