The other obvious model for growth is logistic.

Sam Scheiner

"Gus Gassmann" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Donald Burrill wrote:
>
> > If you're dealing with a growth curve, is it possible that an
> > exponential curve would fit?  (I know that for some segments of an
> > organism's history the expected growth rate follows an exponential
> > function, which implies a constant doubling time when the predictor is
> > the age of the organism, until constraints of available space (or of
> > maturation, I suppose) prevent the exponential increase from
> > continuing.)
> >
> > Your predictor, I gather, is fertilizer concentration, not time;
> >  I can't tell whether an exponential (or logarithmic) function is at all
> > reasonable, but such models might be worth trying.  I'd be inclined to
> > distrust a polynomial of any order, particularly > 2, because I should
> > think the underlying trend should be monotonically increasing, and a
> > polynomial is not "naturally" monotonic, so to speak:  I suspect the
> > 6th-order polynomial is useful mainly in sharpening the corner, so to
> > speak, between slower growth rates at lower concentrations and faster
> > growth rates at higher concentrations.  (Certainly a similar effect
> > occurred with some data I once had occasion to work with, dry mass of
> > organism as a function of time.  An exponential nicely fit the data;  it
> > took a 4th-order polynomial to represent adequately the shape of the
> > empirical curve, mainly due to having to sharpen that lower-right corner
> > much more than one would get from a parabola.)
> >
> > For fitting Y as a function of X, if the response curve is exponential,
> > one expected form of relationship would be  Y = a*e^(b*X).  Taking
> > logarithms (natural logs, here),  log (Y) = log(a) + b*X
> >  which is a nicely linear function.
> >
> > If plotting  log(Y)  as a function of  X  does not produce a (nearly)
> > straight line in the scatterplot, you might also try  log(Y) vs. log(X)
> > and/or Y vs. log(X).  (I have no theoretical reasons for these
> > suggestions, only looking for a functionality that looks reasonably
> > linear:  when one has found such a thing, one can then worry about
> > whether it can be justified on grounds other than sheer empiricism.)
> >
> > And of course if  Y vs. X  is quadratic in X, you might try plotting
> >  sqrt(Y) vs. X.
>
> Don't forget reciprocal relationships: y = a/x (or y = a/(x-b) ). The
latter
>
> is tricky because if you have to estimate b from the data, you no longer
> have a linear relationship in the coefficients, but the former can be used
> in the straightforward manner.
>


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