On Sun, 25 Apr 2004 09:48:28 +0100, "Rod" <[EMAIL PROTECTED]>
wrote:

> Strictly speaking it is still non-linear because the errors are centred on x
> not e^-x. Probably won't make a big difference though
> 

Aren't the errors centered in Y? 

Isn't X  assumed to be measured without error?
(so, e^-x  is equally without error.)

-- 
Rich Ulrich, [EMAIL PROTECTED]
http://www.pitt.edu/~wpilib/index.html
.
.
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