> Kirby got the trapezoidal integration rule wrong.
> This is the corrected version.
>
> def integrate(f,a,b,n=1000):
> sum = 0
> h = (b-a)/float(n)
> for i in range(1,n):
> sum += f(a+i*h)
> return h*(0.5*f(a)+sum+0.5*f(b))
>
Here's the same thing using a generator expression (which is good for
situations like this):
def integrate2(f,a,b,n=1000):
thesum = 0
h = (b-a)/float(n)
thesum = sum(f(a+i*h) for i in range(1,n))
return (h/2)*(f(a) + f(b)) + thesum*h
Kirby
See: "Composite Trapezoidal Rule"
http://math.fullerton.edu/mathews/n2003/TrapezoidalRuleMod.html
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