Hi All, I am using the following code for mapping a Java Object to DB object (Oracle). stmt.registerOutParameter (1, Types.STRUCT, 'DB_OBJ_TYPE");
The oracle object contains varrays as its attributes. (A procedure fetches the records, puts them in the varray and the object is created with these varrays). Though the procedure is taking very less time to execute and create the object, the registering of out parameter is taking a lot of time. Is there any faster way to do this. Will JDBC 2.0 be faster. I am using this driver - 'oracle.jdbc.driver.OracleDriver' and app server is WL 5.1.0. Is there any method of knowing the JDBC version. Thanks Prasad. =========================================================================== To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff EJB-INTEREST". For general help, send email to [EMAIL PROTECTED] and include in the body of the message "help".
