Don,
I don't know the exact formula, but I can say that the power is
proportional to the voltage squared.
If you really want to do that, I would suggest that you set the power to
several different levels and compare the square of the VFWD to the power
output - see what the common factor is and use that - or make a graph.
If you have the KPA500, I would thnk determining the power out is even
easier - the KPA500 displays the power, and that will be correct *if*
the SWR is low.
73,
Don W3FPR
On 11/3/2013 7:49 AM, Goldtr8 (KD8NNU) wrote:
Does anyone know how to convert the VFWD readings from the KAT500 software to
actual watts out?
If I knew this reference calculation then I could eliminate my W2 from the
system. I guess I could do lots of measurements to get close but if some knows
and can share it would be a lot quicker.
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