Oh for Pete's sake!
"Left to their own, most hams will complicate a simple subject beyond
recognition."
Art, W6RMK [SK]
who taught me the code at age 12 and said the above while explaining how
my link coupling to the "tank" matched the 6L6 plate circuit impedance
[several thousand ohms], to the low impedance at the end of the 75-ohm
twin-lead from my 40m dipole.
And, to forestall a posting storm from those racing to the keyboard to
point out the "75 ohm twin-lead typo," there were at least two grades of
commercial 75 ohm twin-lead, a fairly small, flexible version for lower
power, and a much heavier, somewhat unwieldy version for high power.
Been years since I've seen them. For the less financially endowed [e.g.
me], there was also lamp cord ... close enough.
73,
Fred ["Skip"] K6DGW
Sparks NV DM09dn
Washoe County
On 2/19/2018 11:45 PM, David Gilbert wrote:
No, I don't know that at all. I understand the reluctance to use that
terminology, but strictly speaking you're wrong. Reactance networks
are reciprocal ... they don't care in the least which direction power
is heading. The combination of the feedline, the "antenna tuner", and
the output impedance of the transmitter reflect back along the
feedline to the antenna the same reactance that you would use at the
antenna feed point to zero out the total reactance there ... i.e.,
"tune" it. The only difference lies with their respective losses.,
and if you had lossless feedline and lossless components there would
be no difference at all.
It's basic network physics, and reciprocity is reciprocity.
73,
Dave AB7E
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