" from math import * w2dbm = lambda x: 10 * log10(x/10) + 30 dbm2w = lambda x: 10 ** ((x-30)/10) iso = lambda pwr_W, iso_dB: dbm2w(w2dbm(pwr_W) - iso_dB)
and now something like >>> iso(1500, 60) 0.001500 tells you that 1500 W with 60 dB isolation leaks 1.5 mW to the other port." Does dividing 1,500 by 10 to the power of 6 really need a computer and a Python script? Why not just move the decimal point 6 times? 73, Andy, k3wyc ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:Elecraft@mailman.qth.net This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to arch...@mail-archive.com
