For those who didn't read the appendix - here's a brief summary of Belgium's elections.  Party list voting decides the number of seats per party.  Within a given party, you may either vote for the standard party order, in which case your vote is treated like a STV vote, or you may vote for multiple candidates, which essentially gives you the power of multiple voters, although your votes do not transfer.  But so many voters vote the standard order that it ends up dominating anyway.

Philippe Errembault wrote:

Some people among us think that we just should divide the votes
by the number of candidates you favored (if you vote for N
candidates, each one will receive 1/N vote) but I think this is not
fair, since if you vote for each candidates but one in the list, your
vote will not express more than if you vote only for one candidate.
In fact you will favor the party order. By the way, this solution would
even be worse for the FBC.

Better would be to abandon the "case de tête" option altogether.  If folks are too lazy to vote for candidates within the party, then just count their vote for how many seats the party gets overall.

As far as how to count the votes within the party, I'd suggest proportional Approval voting:

http://groups.yahoo.com/group/election-methods-list/message/6367

-Adam


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