Proportional representation election. 4 to be elected. 22 ABCDE 21 BCDEA 20 CDEAB 19 DEABC 18 EABCD 100 No CW or CL. Which group of voters should move to their second choice ? If E loses (i.e. an IRV tiebreaker), then 40 A 21 B 20 C 19 D 100 Each legislator would have a voting power in the legislative body equal to the number of votes that he/she receives. Doing this avoids all the fractional math connected with STV. Same votes. Elect 2 22 ABCDE 21 BCDEA 20 CDEAB 19 DEABC 18 EABCD 100 The general head to head case is-- Test Winner(s) Test Loser Test Other Loser(s) TW TL TOL First choice Votes TOL to TW TOL to TL -TOL + Later TOL choices TW TL zero Totals A TW is a CW, CL or in a tie. A TW which gets a Droop Quota in all of his/her combinations obviously is a CW. Sample combinations--- TW TL TOL A,B C D,E 22,21 20 19,18 19 -19 18 -18 59, 21 20 0,0 A,B E C,D 22,21 18 20,19 20 -20 19 -19 22,21 57 0,0 If E loses (due to the various ties), then-- 40 A (more than Droop Quota) 21 BCDA 20 CDAB 19 DABC 100 A, B>C A, C>D A, D>B If D loses, then 59 A (more than Droop Quota) 21 BCA 20 CAB 100 A,B > C Final 79 A, 21 B