Hi again,

I should add one small point to the message I posted a few minutes ago.

Assuming the orderings do not need to be strict orderings, and assuming 
(Withdrawal)PluralityRule is the method used to tally, there is a question 
about how to 
count an ordering that ranks two or more non-withdrawn candidates at its top.  
Its weight 
could either be split or counted fully for each of those candidates.  I favor 
the latter, 
but I think it would tend to work well either way.

--Steve
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