Very interesting method. Just a quick question. The article mentions that rank-order methods would be really tough to do. Wouldn't the method just be two votes with the correct rank-order and one with the reverse order? If you wanted A>B>C, you'd have two votes for that and one for C>B>A. Borda would end up with the score A=4, B=3, C=2, which is the same order, just shifted. Condorcet might have problems with completion rules when there is a circular tie, but a Condorcet winner should be the same either way.
I'd try to figure it out, but I'm at work now. :D Michael Rouse [EMAIL PROTECTED] ---- election-methods mailing list - see http://electorama.com/em for list info
