Here's a version that is both clone proof and monotonic: The winner is the alternative A with the smallest number of ballots on which alternatives that beat A pairwise are ranked in first place. [shared first place slots are counted fractionally] That's it. This method satisfies the Smith Criterion, Monotonicity, and Clone Independence. I'll leave it up to Chris to tell us which of Woodall's criteria are not respected by this method. I also like the stochastic version that chooses by random ballot from the set of alternatives S, such that for each A in S, at most fifty percent of the first place slots are taken up by alternatives that beat A pairwise. Forest
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