If instead of Simmons's choice 4:2:2:2 for the city populations, we use
4:4-k:k:4-k then

* with k=2 we get Simmons populations and 60:40 majorities.
* with k=1 we get 7:4 majorities (or more)
* when k drops to 0 we get 66.66% majorities for every pair,
which is maximum possible, and city C becomes unoccupied.

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Warren D. Smith
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math.temple.edu/~wds/homepage/works.html
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