On 4.8.2011, at 2.09, Jameson Quinn wrote:

> Free riding in some form is inevitable in a good system. (That is, any system 
> which avoids free riding entirely would be horribly warped by that necessity).

How about tree methods? If candidates are ordered as a binary tree (instead of 
an open list), then there are no choices between three or more branches, and 
related free riding becomes impossible.

Juho




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