Can you elaborate on the code you have in mind? This sounds like a general
characteristic of pipes and not something specific to Map.get_lazy.
On Monday, March 20, 2017 at 6:48:46 AM UTC-4, David Long wrote:
>
> That's not entirely accurate. In my case I was using a series of pipes so
> I did not have access to the map. My case might be very niche, though.
>
> On Mon, Mar 20, 2017, 12:44 AM José Valim <jose....@plataformatec.com.br
> <javascript:>> wrote:
>
>> The reason why get_lazy does not pass the map is because you already have
>> the map, since you pass it as first argument.
>>
>> On Mon, Mar 20, 2017 at 03:44 David Long <david....@gmail.com
>> <javascript:>> wrote:
>>
>>> I was working on some code that would simply test if one key was in a
>>> map and return it's value, and otherwise return a different key's value.
>>>
>>> The map had a form like the following:
>>>
>>> %{
>>> oncall: "dlong",
>>> overrideoncall: "jsmith",
>>> ...
>>> }
>>>
>>>
>>> If there was someone overriding on call then their name would be in the `
>>> overrideoncall` key, otherwise the key would not be in the map.
>>>
>>> I think this could be a nice use for `Map.get_lazy`, if the function had
>>> the original map passed in, allowing me to write the code as follows:
>>>
>>> Map.get_lazy(on_call_group, :overrideoncall, &(&1[:oncall]))
>>>
>>>
>>> Before I wrote a pull request, I thought I'd see if this is a feature
>>> that makes sense to others?
>>>
>>> --
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>>
>> *José Valim*
>> www.plataformatec.com.br
>> Skype: jv.ptec
>> Founder and Director of R&D
>>
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