I think Martin was asking what would happen if the function run by a
repeating timer cancelled the same timer, in the case where the repeating
timer is delayed more than REPEAT*2 seconds due to a popup or something. I
was trying to explain that it does not result in the timer being triggered
more (or less) than the case where the timer that runs the function is not
delayed; the timer cancellation behaviour is consistent between the two
cases.
If the timer function cancels the timer, the timer should not
be triggered again. So if three repetitions for times T+2, T+4 and T+6
have been delayed until time T+7, and the first call (which should
have been at T+2) cancels the timer, the timer should not reschedule
itself for T+4, and the function should not be called again.
I just clarified that in the Lisp Manual.
Does the observed behavior match that or not? I think your words
say yes, but I can't really be sure.
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