Absorbtion loss is given by

A(dB) = 3.34 t (f(Mhz)Gu) where

t = thickness in mils (sorry, my book is not metric based)
G = conductivity relative to copper (G = 1 for copper)
u = relative permeability to vacuum

Reflection loss is given by

R(dB) 20 log [(K_1)^2/4K] which is approx 20 log [Z(w)/4Z(b)] for K>10 

where Zw is the wave impedance and Zb is the surface impedance.

For plane waves

R(dB) = 108 + 10 log [G/uf(MHZ)]

All this is from EMC Handbook, Vol 3, Don White Consultants, 1973.

Richard Woods
Sensormatic Electronics
Tyco International





-----Original Message-----
From: Wani, Vijay (V) [mailto:vw...@dow.com]
Sent: Friday, November 09, 2001 10:36 AM
To: 'emc-p...@majordomo.ieee.org'; 'si-l...@freelists.org'
Subject: emi shielding



hello:

as we know, threre are two main component of shielding effectiveness.
(Absorbtion and Reflection). is there any way to find out.. what percentage
of overall shielding is due to absorbtion / reflection for a given material?

thank you in advance.

Vijay Wani
Dow Chemical

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