Kyaw:

It may help to see IEC Technical Report TR 60825-10 "Safety of laser products
Part 10: Application guidelines and explanatory notes to IEC 60825-1,"
Sections 9 Intrabeam Viewing, and 10, Extended Source Viewing.

Also see IEC Technical Report TR 60825-14 "Safety of laser products Part 14: A
user's guide," which is a "guide" to 60825-1, and contain numerous worked
calculation examples, etc.

These were written as informative and educational texts to the normative parts
of IEC 60825-1.

  
William T. Sykes
Lucent Technologies EH&S
Product Safety/Conformance Manager
Room 7B-516A
600-700 Mountain Avenue
Murray Hill, NJ  07974-0636 
(908)582-6937
   


From: [email protected] [mailto:[email protected]]On Behalf Of KYAW HTIN
AUNG
Sent: Thursday, June 08, 2006 12:22 PM
To: EMC PSTC
Subject: Laser safety AEL calculation - angular subtense and C6


Dear Good People

Our product is a class II laser scanning engine. The
original source of laser is from a laser diode. It
passes through a lens and strikes two subtended
mirrors before it goes out for scanning. According to
IEC 60825-1, AEL limit is defined as C6x10-3W where C6
is based on angular subtense (alpha). If alpha is less
than or equal to alpha min, C6 = 1. If alpha is
between min and max, C6 is alpha/alpha min where alpha
min is 1.5mrad.

The debate right now is how to define alpha value to
get C6. I was told to consider it is intrabeam viewing
so that alpha is always min and C6=1. I have no
objection that it is intrabeam viewing but I do not
accept that alpha is always min for intrabeam viewing.
In our case, I consider it is an enlarged source, not
a point source. Enlarged source will create enlarged
image at the retina of our eye. So alpha will be
greater than min value of 1.5mrad and C6 will be
greater than 1.

Anybody can shed the light on this topic? Or any
reference to a good info source?

Thanks in advance

Kyaw

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