I am using a Panasonic AQH3213A PhotoMOS optical isolator to control a
small contactor.

At 110VAC the contactor coil draws 30mArms.
The coil contacts are wired to a PCB via a terminal block plug and socket.

On the PCB is a series 10ohm fusible resistor, and a SMBJ400AC
bidirectional zener.

When the switch opens at peak current (42mA) there is 0.1J of energy in the
coil that gets absorbed by the zener.

The zener
* clamps at a voltage way below the voltage rating of the optoMOS switch.
* is rated at 600W for 8.3msec and is subject to only 13W for a similar
period.

The UL test engineer says that the optoMOS should be "pilot duty" rated
(the part I am using does have this rating).

Does anyone know what triggers the requirement for a "pilot duty" rating?
Is this defined in a standard somewhere?

This useful link identifies "contact rating codes"
https://na.industrial.panasonic.com/blog/what-pilot-duty-rating-how-it-obtained

The lowest rating E300 is for 110V 1.8A (make) 0.3A (break)

Technically speaking, my switch is not connected to the contactor .. there
is a two-component network in between
Does UL have the capacity or procedures in place to understand and accept a
circtuit analysis that shows my circuit as safe?

Jon Keeble

Wattwatchers.

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