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* The equipment is tilted in all directions such that the base of the equipment is at an angle up to and including 10°; or Only one direction is significant: The side of the base that is closest to the center of gravity. This is the worst case. If the equipment passes this tilt direction, it will pass all the other tilt directions. * The equipment is placed on a plane at an angle of 10° from the horizontal and rotated slowly through an angle of 360° about its normal vertical axis; or See above. * The equipment is placed on a horizontal non-skid surface and subjected to a force equal to: - 50 % of the weight of the unit vertical downwards, but not more than 100 N. If, during the test, the supporting surface prevents the equipment from overturning, the test shall be repeated such that the supporting surface is not used to pass the test; and For the equipment not to tilt over, the moment of the vertical force applied to the equipment must not exceed the moment of the center of gravity. - 13 % of the weight in all horizontal directions but not more than 250 N, Again, if the force moment exceeds the center of gravity moment, the equipment will tip over. that is applied to the worst case positions on the equipment by means of a suitable test apparatus having a flat surface of approximately 125 mm by 200 mm, in such a way as to produce the maximum overturning moment. The test may be applied at any height not exceeding 1,5 m from the base of the equipment. The test force shall be discontinued if the equipment remains stable after being tilted 10° from vertical. The worst-case position for maximum overturning moment is maximum distance from the center of gravity. Assuming the center of gravity is at the geometric center (which is close for most equipment), all you need to determine if the equipment will fall over is the minimum width and the maximum height to determine if the equipment will tip over for the tilt test, the downward force test, and the horizontal force test. Best regards, Rich Note: To convert weight, kg, to force, N, multiply kg by 9.81. - ---------------------------------------------------------------- This message is from the IEEE Product Safety Engineering Society emc-pstc discussion list. To post a message to the list, send your e-mail to <[email protected]> All emc-pstc postings are archived and searchable on the web at: http://www.ieee-pses.org/emc-pstc.html Attachments are not permitted but the IEEE PSES Online Communities site at http://product-compliance.oc.ieee.org/ can be used for graphics (in well-used formats), large files, etc. Website: http://www.ieee-pses.org/ Instructions: http://www.ieee-pses.org/list.html (including how to unsubscribe) List rules: http://www.ieee-pses.org/listrules.html For help, send mail to the list administrators: Scott Douglas <[email protected]> Mike Cantwell <[email protected]> For policy questions, send mail to: Jim Bacher: <[email protected]> David Heald: <[email protected]>
