On 10 March 2010 11:26, Andy Pugh <a...@andypugh.fsnet.co.uk> wrote:
> V = (H.A)/s. > > If we solve for phase current then at 2000rpm you only have enough > voltage to push a peak current of 1.6A through the windings. Perhaps This isn't exactly true... I was looking at the definition of the Henry, not the equation for inductance (I had a nagging doubt that there as a 1/2pi missing) V = L(dI/dt) Assuming sinusoidal current variation (not true, but never mind) I = A.sin(2.pi.f.t) The max value of dI/dt is then 2.pi.A.f So, at the limit your coil current is V/(2.pi.L.f) = 0.25A, so you don't have a lot of torque left. -- atp ------------------------------------------------------------------------------ Download Intel® Parallel Studio Eval Try the new software tools for yourself. Speed compiling, find bugs proactively, and fine-tune applications for parallel performance. See why Intel Parallel Studio got high marks during beta. http://p.sf.net/sfu/intel-sw-dev _______________________________________________ Emc-users mailing list Emc-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/emc-users
