Hi,
I want to write a little app that needs to automatically discover existing
peers inside a LAN.
Each instance launches one host that accepts a given number of peers. Then
it attempts to connect to the ENET_BROADCAST address. Since new hosts can
appear at random, a new connection attempt is made each second. Thus after
a while every peer should connect to every existing host in the LAN.
Now let's say I start with two hosts A and B with 10 peers each.
In vanilla ENet implementation, each connection attempt issued by host A
will bind itself to host B, resulting in all peers on a given host
connected to the other host. I have changed ENet code as follows so that
when several connection attempts are issues by host A, only one can ever
succeed with host B:
in enet_protocol_handle_connect()
{
...
for (currentPeer = host -> peers;
currentPeer < & host -> peers [host -> peerCount];
++ currentPeer)
{
if (currentPeer -> state != ENET_PEER_STATE_DISCONNECTED &&
currentPeer -> address.host == host -> receivedAddress.host &&
currentPeer -> address.port == host -> receivedAddress.port /*&&
currentPeer -> connectID == command -> connect.connectID*/) //
THIS PART IS DISABLED TO PREVENT MULTIPLE CONNECTIONS BETWEEN THE SAME HOSTS
return NULL;
}
...
}
However, this is not enough: I observe that host A will only bind one peer
to host B successfully, but host B will also successfully bind one peer to
host A, thus resulting in hosts A and B having each 2 peers connected to
their counterpart. How can I prevent this?
And more generally, what is the interest of authorizing several peers of a
given host to connect to another host?
Regards,
--
Benoit.
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