> From: Brendan Eich <bren...@mozilla.com>
> Date: June 23, 2011 0:21:17 GMT+02:00
>
>> Is there no per-call cost whatsoever to adding static super?
>
> No, it's static -- an internal property of the function object set once on
> creation and (in my view) never changed thereafter unless unobservably
> (Allen's point about optimizing Object.defineMethod when "handing off" an
> otherwise-useless function expression).
How does a function get access to its properties? Doesn’t the ability to access
"thisFunction" incur any costs? I would expect static super to work as follows:
var Sub = Super <| {
foo: function me(x) {
me.super.foo.call(this, x);
}
}
Does the named function expression cost nothing here?
--
Dr. Axel Rauschmayer
a...@rauschma.de
twitter.com/rauschma
home: rauschma.de
blog: 2ality.com
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