The proposal for <| cites these usage examples:
- Setting the prototype of a function to something other than
Function.prototype
let f = EnhancedFunctionPrototype <| function () {}
- Parrallel constructor/instance prototype chains
let superclass = function () {};
//define a constructor method
superclass.new = function () {return (new this()).initialize()};
//define a instance method
superclass.prototype.initialize = function () {return this};
let subclass = superclass <| function () {};
...
Question: When RHS is function expression, does it distinguish if LHS is
function to select one of the (different) behaviours from above?
Herby
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