function f(a, b) {
return [a, b];
}
Currently:
f(1, 2); // [1, 2]
Whereas...
// single parameter, implicit arguments pseudo-array:
f(1, 2);
|a| would be magically be treated like a ...rest param that wasn't really
an array, but instead a implicit arguments pseudo-array?
// [[1, 2], undefined]
No, just another way to describe the current situation, where
function f() {return [...arguments]} // pseudo code
f(1,2) // [1,2]
or, if we make the arguments explicit
function f(...arguments) {return [...arguments]} // pseudo code
f(1,2) // [1,2]
and explicit formal parameters would be destructured from arguments,
so
function f(a,b) {return [a,b]}
f(1,2) // [1,2]
The solutions shown above using [] also create ambiguity with:
- MemberExpression[ Expression ]
- CallExpression[ Expression ]
Given:
function foo(value) {
return value;
}
foo.prop = "Some data";
Currently:
foo("prop"); // "prop"
foo["prop"]; // "Some data"
ah, yes, I knew there had to be a serious flaw somewhere... sigh
Claus
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