On 11/26/2013 03:00 PM, André Bargull wrote:
On 11/26/2013 02:28 PM, Claude Pache wrote:
>/ From the thread [1], I guess that parsing correctly the following thing
would be obnoxious (at best)?
/>/
/>/ (a = yield/b/g) =>* {}
/>/
/>/ —Claude
/
Indeed.
And you can make even more obnoxious parses of the hypothetical combination of
=>*, default parameters, and retroactive yield-scope:
(a = yield/"/) =>* (/"/g)
Are the two /"/'s regexps or is "/) =>* (/" a string token?
Waldemar
Are you sure? The `(a = yield/b/g)` part is parsed at first as a parenthesised
expression and only later (after the `=>` token) reinterpreted as an
ArrowFormalParameters grammar production.
- André
Fine, so do this one instead:
(a = yield/"/g, b = yield/"/g) =>* {}
Does this generator have one or two parameters?
Waldemar
_______________________________________________
es-discuss mailing list
es-discuss@mozilla.org
https://mail.mozilla.org/listinfo/es-discuss
