`super.foo(x)` is equivalent to ```js Object.getPrototypeOf(me.[[HomeObject]]).foo.call(this, x); ```
(where `me` refers to the current function) On Dec 9, 2013, at 18:28 , James Long <longs...@gmail.com> wrote: > I'll keep digging through the spec, but if someone has a quick example > what ES5 code I could compile to for roughly the same semantics, that > would be helpful. -- Dr. Axel Rauschmayer a...@rauschma.de home: rauschma.de twitter: twitter.com/rauschma blog: 2ality.com
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