Le 15 sept. 2014 à 23:19, Kevin Smith <zenpars...@gmail.com> a écrit :
>
>
> Isn't the latter (since it specifies ": super(x)") actually identical to
>
> constructor(x, y) {
> this = new super();
> this.y = y;
> }
>
> IOW, isn't it "I am constructor only and will throw if {[Call]]ed)?
>
> No. The idea is that the "class create expression" is only called when the
> constructor is "new"d. It's purpose is to set up the "this" value when
> [[Construct]] is called, exactly as @@create used to.
>
When you write:
constructor(x, y) {
if (new^)
this = new super(x);
this.y = y;
}
is it intentional that you call the super-constructor only when you have been
called with `new`, and not in case of a direct call?
For instance, if I wanted to support to be called through the legacy
`SuperConstructor.call(this, ...args)` trick in addition to be new’d, I'd
rather try the following:
constructor(x, y) {
if (new^)
this = new super(x);
else
super.constructor(x);
this.y = y;
}
The point here is that the purpose of the constructor method is not only
allocation, but also (and primarily) initialisation.
—Claude
_______________________________________________
es-discuss mailing list
es-discuss@mozilla.org
https://mail.mozilla.org/listinfo/es-discuss
