Kevin Smith wrote:
```js export default function a() {} a = 2;```(This should be 2, right?)I *think* the "default" binding in this case would still point to the function. I find this particular example completely baffling, to be honest.
This seems clear. As Dave said, he originally proposed an '=' in between 'default' and the *expression* to evaluate on the right. That design remembrance should make clear that the default export is a function expression (not function declaration) with 'a' the name only in the scope of that function (either for recursion or as a downward funarg).
The 'default' binding won't be mutated via the final 'a = 2' statement, so the default-exported value is still the result of evaluating the function a(){} expression.
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