On Mar 16, 2015, at 10:32 AM, Coolwust wrote: > From ES 6, section 7.3.14, there is an abstract operation `Construct (F, > [argumentsList], [newTarget])`, so if I have the following code `var foo = > new bar()`, then `newTarget` is the same as `F`, which is `bar`. > > My question is, in what situation, `F` is **NOT** the same as `newTarget`? > And what is `newTarget` really?
super() calls within constructors see http://people.mozilla.org/~jorendorff/es6-draft.html#sec-super-keyword-runtime-semantics-evaluation 3rd algorithm allen
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