And to answer, the `'k'` in `Object.prototype.toString.call( 'k' )` get
auto-boxed. That's why.

On Fri, Jan 1, 2016 at 9:29 AM, Domenic Denicola <[email protected]> wrote:

> This mailing list is largely meant for the further development of
> JavaScript as a language (new feature design, spec review, etc.), and not
> for questions on how JavaScript works. StackOverflow is indeed a better
> venue for such questions.
>
>
>
> *From:* es-discuss [mailto:[email protected]] *On Behalf Of *Arup
> Rakshit
> *Sent:* Friday, January 1, 2016 12:28
> *To:* Bob Myers <[email protected]>; [email protected]
> *Subject:* Re: Confusion with Object.prototype.toString and primitive
> string datatype
>
>
>
> Hi Bob,
>
>
>
> Don’t we have any mailing list to ask JavaScript questions? I like mailing
> list rather than StackOverflow.com <http://stackoverflow.com> :(
>
>
>
>
>
>
>
> On Jan 1, 2016, at 10:56 PM, Bob Myers <[email protected]> wrote:
>
>
>
> Seems like a good Stack Overflow question, take it there.
>
>
>
> On Fri, Jan 1, 2016 at 10:54 PM, Arup Rakshit <[email protected]> wrote:
>
> Hi,
>
> Consider the below simple code :
>
> 'k' instanceof String; // false
> new String('k') instanceof String; // true
>
> Now, When I am inspecting them as below why in both cases the output comes
> as [object String] ?
>
> The below is understood as per the result of the `instanceof` operator.
>
> Object.prototype.toString.call( new String('k') );  // "[object String]”
>
> My confusion comes when I see the below code output :
>
> Object.prototype.toString.call( 'k' );  // "[object String]”
>
> Can anyone please explain it ?
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>
>
>
>
>
> _______________________________________________
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>
>
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